The superposition takes place between two waves of frequency f and amplitude a. The total intensity is directly proportional to
If two waves of same frequency and same amplitude respectively, on superimposition produced a resultant disturbance of the same amplitude, the waves differ in phase by
Two sources of sound A and B produces the wave of 350 Hz, they vibrate in the same phase. The particle P is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is 0.3 mm and 0.4 mm, then the resultant amplitude of the point P will be when AP – BP = 25 cm and the velocity of sound is 350 m/sec
Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead byπ/3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter
The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when
If two waves having amplitudes 2A and A and same frequency and velocity, propagate in the same direction in the same phase, the resulting amplitude will be
The intensity ratio of two waves is 1 : 16. The ratio of their amplitudes is
Two waves of same frequency and intensity superimpose with each other in opposite phases, then after superposition the
The displacement of a particle is given by x=3sin (5πt)+4cos(5πt)
The amplitude of the particle is
If the ratio of amplitude of wave is 2 : 1, then the ratio of maximum and minimum intensity is