The displacement of a particle starting from rest (at t=0 ) is given by s=6t²-t³ . The time in seconds at which the particle will attain zero velocity again, is
What is the relation between displacement, time and acceleration in case of a body having uniform acceleration
Two cars A and B at rest at same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with constant acceleration of 4m/s^2, then B will catch A after how much time
The motion of a particle is described by the equation x=a+bt^2 where a=15 cm and b=3 cm/s2. Its instantaneous velocity at time 3 sec will be
A body is moving according to the equation x=at+bt²-ct³ where x= displacement and a ,b and c are constants. The acceleration of the body is
A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec
The distance travelled by a particle is proportional to the squares of time, then the particle travels with
Acceleration of a particle changes when
The motion of a particle is described by the equation u=at. The distance travelled by the particle in the first 4 seconds
The relation 3t=√3x+6 describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is
A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 m, the magnitude of the force is
The average velocity of a body moving with uniform acceleration travelling a distance of 3.06 m is 0.34 ms–1. If the change in velocity of the body is 0.18ms–1 during this time, its uniform acceleration is
Equation of displacement for any particle is s=3t³+7t²+14t+8m . Its acceleration at time t=1 sec is
The position of a particle moving along the x-axis at certain times is given below :
| t (s) | 0 | 1 | 2 | 3 |
| x (m) | –2 | 0 | 6 | 16 |
Which of the following describes the motion correctly
Consider the acceleration, velocity and displacement of a tennis ball as it falls to the ground and bounces back. Directions of which of these changes in the process
The displacement of a particle, moving in a straight line, is given by s=2t²+2t+4 where s is in metres and t in seconds. The acceleration of the particle is
A body A starts from rest with an acceleration a_1. After 2 seconds, another body B starts from rest with an acceleration a_2. If they travel equal distances in the 5th second, after the start of A, then the ratio a_1:a_2 is equal to
A body of 5 kg is moving with a velocity of 20 m/s. If a force of 100N is applied on it for 10s in the same direction as its velocity, what will now be the velocity of the body
A particle starts from rest, accelerates at 2 m/s2 for 10s and then goes for constant speed for 30s and then decelerates at 4 m/s2 till it stops. What is the distance travelled by it
The engine of a motorcycle can produce a maximum acceleration 5 m/s2. Its brakes can produce a maximum retardation 10 m/s2. What is the minimum time in which it can cover a distance of 1.5 km
The path of a particle moving under the influence of a force fixed in magnitude and direction is
A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is
A student is standing at a distance of 50metres from the bus. As soon as the bus begins its motion with an acceleration of 1ms–2, the student starts running towards the bus with a uniform velocity . Assuming the motion to be along a straight road, the minimum value of , so that the student is able to catch the bus is
A body A moves with a uniform acceleration a and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity v. The two bodies meet after a time t. The value of t is
A particle moves along X-axis in such a way that its coordinate X varies with time according to the equation x=(2-5t+6t²)m . The initial velocity of the particle is
