A particle has velocity given by v = 20 + 0.1 t²then it has

The displacement is given by x = 2t²+ t + 5, the acceleration at t = 5 sec will be

A particle is moving so that its displacement is given as s=t³-6t²+3t+4  Its velocity at the instant when its acceleration is zero will be

If velocity of a particle is given by V=10+2t²m/s. The average acceleration between 2 and 5 s is

If the displacement of a particle varies with time as √x=t+7 , the

A truck travelling due north at 20 ms¯¹turns west and travels with same speed. What is the change in velocity ?

If relation between distance and time is s = a + bt + ct², and initial velocity and acceleration :

A car starts from rest and has an acceleration a = t. A truck is moving with a uniform velocity of
6 m/s.  At what distance will the car overtake the truck? (at t = 0 both start  their motion in the same direction from the same position)

Two balls are dropped from the same point after an interval of 1 s. If acceleration due to gravity is 10 m/s², what will be the separation 3 seconds after the release of first ball?

If velocity varies with time as n = 4t, find the distance travelled by the body in the interval of 2 s to 4 s.

A particle moves along a straight line OX. At a time t (in seconds ) the distance x (in metres) of the particle from O is given by x = 40 + 12t – t³

How long would the particle travel before coming to rest ?

The position x of a particle with respect to time t along x-axis is given by x = 9t² – t³ where x is in metre and t in second. What will be the position of this particle when it achieves maximum speed along the + x direction?

A particle is moving eastwards with a velocity of 5 ms¯¹. In 10 second the velocity changes to 5 ms¯¹ northwards. The average acceleration in this time is :

The displacement  of a particle, starting from rest (at t = 0) is given by

                                                                s = 6t² – t³

A particle is moving along x axis with constant acceleration. At t = 0 , the particle is at x = 3 m and dx/dt = + 4 m/s. The maximum value of x co-ordinate of the particle is observed 2 seconds later. Starting from t = 0 sec after what time particle reaches its initial position again?            

Which one of the following equations represent the motion of a body with finite constant non-zero   In these equations y denotes the displacement of the body at time t and a,b and c are the constant of the motion

A ball is thrown upward and reaches a height of 64 feet, its initial velocity should be (g = 32 ft/sec²)

The initial velocity of a particle (at t = 0) is u and the acceleration f of particle at time t is given by
f = at. Where a is a constant which of the following relation for velocity v of particle after time t is true?