Part 4-Motion in a plane medium

A particle is fired with velocity u making angle θ with the horizontal. What is the change in velocity when it is at the highest point ?

A ball is thrown at different angles with the same speed u and from the same point and it has the same range in both the case, If y1 and y2 be the height attained in the two cases, then y1+y2 = .... :-

At what angle with the horizontal should a ball be thrown so that its range R is related to the time of flight as R = 5T². (Take g = 10ms¯²) : -

The maximum range of a projectile fired with some initial velocity is found to be 1000 metre. The maximum height (H) reached by this projectile is :-

The vertical height of the projectile at time t is given by y = 4t – t² and the horizontal distance covered is given by x = 3t. What is the angle of projection with the horizontal?

A bomb is fired from a cannon with a velocity of 1000 m/s making an angle of 30º with the horizontal. What is the time taken by the bomb to reach the highest point-

For a projectile the ratio of maximum height reached to the square of flight time is- (g = 10 ms¯²)

If a projectile  is thrown such  that range [R] is four times than the height [h] attained then angle of projection is-

The range of projectile is 50 m when θ is inclined with horizontal at 15°. What is the range when θ becomes 45° -

A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacement x and y vary with time t in second as: x = 10√3  and  y = 10t – t²

                The maximum height attained by the ball is

The horizontal and verticle distances travelled by a particle in time t are given by x = 6t and
y = 8t – 5t². If g = 10 m/sec², then the initial velocity of the particle is-

In case of a projectile fired at an angle equally indined to the horizontal and vertical with velocity (u). The horizontal range is :-

The range of a projectile when fired at 75º with the horizontal is 0.5km. What will be its range when fired at 45º with same speed :-

A particle is projected with a velocity u making an angle θ with the horizontal. At any instant, its velocity v is at right angles to its initial velocity u ; then v is :-

The speed at the maximum height of a projectile is √3/2 time of its intial speed 'u' of projection. Its range on the horizontal plane :-

What is the ratio of P.E. w.r.t. ground and K.E. at the top most point of the projectile motion :-

A ball is thrown at an angle θ with the horizontal and the range is maximum. The value of tanθ is :-

An arrow is shot into the air. Its range is 200 metres and its time of flight is 5 s. If the value of g assumed to be 10ms¯², then the horizontal component of the valocity of arrow is : -

A particle is projected at an angle of 45º from 8 m before the foot of a wall, just touches the top of wall and falls on the ground on the opposite side at a distance 4 m from it. The height of wall is :-

A projectile can have the same range for two angles of projection. If h1and h2 are maximum heights when the range in the two cases is R, then the relation between R, h1 and h2 is :

A projectile thrown with velocity v making angle θ with vertical gains maximum height H in the time for which the projectile remains in air the time period is

Two projectiles are fired from the same point with the same speed at angles of projection 60º and 30º respectively. Which one of the following is true?